Monday, July 31, 2006

Thanks All-In Magazine

Hey Guys,

Just wanted to brag a little. All-in magazine threw a freeroll with a prize pool of $10,000. Out of 500 plus players I was 3rd. With a total win of $1100. I am little dissapointed. Since, I was the chip leader when it was down to the top 3. Oh well, what can you do about a bad run. Didn't say I was unlucky, I had AJ suited dominated by AQ 3 handed twice.

Goodluck out there.

Tuesday, July 18, 2006

Basic Starting Hand Calculations.

Hey Guys,

Have some of you ever figured out. How many hands you have to see on average before you are dealt AA,KK,QQ,AK,AQ,AJ?

On Average, you will be dealt one of these hands 1 in 20 times. You might have to wait 40 hands. Then you will have two of these hands in a row. All in all it averages out to be 1 in 20.

So just remember, Next time your in sitting at a 9 player table. You will get one of these hands on average, once every 2.3 times around the table. Also, when your holding AJ. Someone will be holding AK, or AQ about 14% of the time.

These are just some calculations. I figured might help if you already didn't know.

Advice from the Pro's: I Don't Agree

Hey Guys,

I have read and heard pro's saying "Move all-in with any ace." "When your short stacked in tournaments with less than 10 blinds." This is ridicilous, obsurd. Unless, you have an ace with a kicker jack or higher. The truth is, I would rather move all-in with 57 offsuit, instead of A6 offsuit in this position.

Okay, I am going to use poker stove. To calculate starting hand equities with 57 offsuit vs. A6 offsuit. These two hands will be enumerated against all (KK,QQ,JJ,1010,AK,AQ,AJ)'s. Will A6 offsuit have a better chance than winning against 57 offsuit? Lets find out.


I enumerated A6 offsuit against all (KK,QQ,JJ,1010,AK,AQ,AJ)'s, The equity of A6off was 27.079%.

Then, I enumerated 57 offsuit against all (KK,QQ,JJ,1010,AK,AQ,AJ)'s. The equity of 57offsuit was 29.630%

Wow, our 57 offsuit has a better chance of winning on average than the A6. Even, against the monster hands. It might be a small percentage, but at this point of a tournament I will take it.

I also ran other hands against all (KK,QQ,JJ,1010,AK,AQ,AJ)'s. I displayed there results below.

A10 offsuited - 27.344%
72 offsuited - 25.106%
J10 offsuited - 29.473%
Q2 offsuited - 26.297%
KQ offsuited - 32.435%
A3 offsuited - 27.697%

If you don't have pokerstove, download it, its interesting and free.

Monday, July 17, 2006

Banning of Online Poker & Interdependence

Hey Guys

I understand why the American Gov't is in an uproar. Especially, about trying to ban online poker. Our economy is losing billions of dollars to offshore internet companies. In a time when we are having budget problems already. Remember, this is considering rake alone. This doesn't mean I am for the banning of internet poker. I am totally for playing poker online.

This American gov't of ours better start adjusting to Interdependence. I don't even know why the Gov't is going to waste time and money on the issue of this. They need to put effort into how they can regulate and tax these operations.

However, I have seen people becoming confused by the Unlawful Internet Gambling Enforcement Act that has been passed by the gov't a few days ago. Cardplayer explains how this doesn't pertain to online poker players here:

http://www.cardplayer.com/poker_news/news_story/1157?class=PokerNews

Poker Links That Deserve Attention Too

Hey Guys,

All of the links below deserve some of your attention as well. I just don't post any link.


Bill's Blog - Profitable Poker Player

No Limit Holdem Advice
- Over 100 original strategy articles by winning online players.

Online Poker RakeBack - Get paid your rake back with Part Time Poker




Hope you enjoy these other links. I will be adding more in the future.

Building a Bankroll for Limit Holdem.

Hey Guys

After taking a 40bb-(Big Bet) swing to the downside. I have decided to make a post about bankroll management. Let's say you are wanting to build up a bankroll to play at the 75/150 limit tables. It's very possible, but it will take work and proper bankroll management.

Okay, you are wanting to build a bankroll to play the 75/150 tables. First of all, you will need to figure out which limits you would like to start out at. I recommend you start out at limits where you can afford 300bb's. There are exceptions though. If you can afford and don't mind to lose $1,000 on any given week. You may not want to start off building a bankroll at the 1/2 limits. You can start off playing at limits that might give you only 150bb's, instead of 300b's of the $1,000.

Whichever, limits you start at. You will need atleast 300 bb's to move up to the next limit. You don't want to risk your bankroll and have to start all over again. Let's say you started off playing the 1/2 limits. Before I would move up to the next limit of 2/4. I would have atleast a bankroll of $1200.

Also, the most important thing here that I can say is. Don't be embarrased if you have to move back down in limits. Let's say you started at the 1/2 limits. You built your bankroll up to 1200 to play at the 2/4 tables. You ran into a bad run of cards. Now your bankroll is $600. To be safe, and not risk going broke. I would move back down to the 1/2 limits. I have done it a few times myself.

This is the basics of proper bankroll management. Also, I personally prefer to have 600-1000 BB's for my agressive play.

Don't forget to email me if you have any questions on anything.

Saturday, July 15, 2006

Combinations Part III: Turn and River

Hey Guys,

I am going to talk about how to use combinations to know your probabilities for turn and river. I talk a lot about combinations, but they are an essential part for poker math.

Let's begin, I am sitting at a table and dealt AK suited of Clubs. To my excitement the flop is { 8h, 10c, Qc }. I am now on a flush draw, inside str8 draw, and I have two overs that can make a pair. I have a total of 18 outs that can make me a pair or better. For people who don't know what outs are. An out is how many cards I have left in the deck to make a hand. In this case a pair or better. Now, I have two cards left for the turn and river. What is the percentage that I will make a pair or better?

Well to start, how many cards have I personally seen. I have been shown 5 cards. The flop has 3 cards, and my hand has 2 cards. Out of a 52 deck I have NOT seen 47 cards.

Now, we start a combination formula. Since we are TAKING FROM the 47 unseen cards. The number 47 is our top part of the combination formula. Then we are selecting 2 cards AT TIME - turn & river. This makes the bottom part of our formula.
(47)
(2)

47 x 46 -----2162
______ = ________ = 1081
2 x 1---------2

1081 is the number of different combinations there are for the turn and river.

Now, for the turn, we now have the number 1081 we can go further into what our percentages are. Remember, I said we had 18 outs. We take 18 outs / 47 unseen cards for the turn.

Now for the river. We have to subtract our outs from the unseen turn cards. In this case 18 outs - 47 unseen cards = 29. We take this answer of 29 and divide it by 47 unseens card. Which would be (29 / 47). If we don't do this part of the process the river will make it easier to hit. We are still not done trying to figure out the river. Now, we divide our 18 outs by the 46 unseen cards on the river that are left in the deck. This looks like 18 / 46. The whole formula will look like this as below:

18 / 47 + (29 / 47) x (18 / 46)

Lets figure out this portion.

2.61 + (1.62 x 2.55)

Lets go further.

2.61 + 4.13

For the final parts to figuring this out. Remember, the number 1081? We take 2.61 / 1081, then 4.13 / 1081.

2.61 / 1081 = 414
4.13 / 1081 = 261

= Combinations: (Turn) 414 / 1081 + (River) 261 / 1081 = 675 / 1081
= Converted to Percentages: (Turn) 38.29% + (River) 24.14% = 62.43%


Okay, I hope this helps anyone out there. Remember, for those who go and use this on an online calculator. What we are assuming here: Is that none of our outs are taken and will not help anyone else to win. All of our outs will win, but we are already beat. We have not yet seen anyone elses cards.

If you go and use cardplayer's online calculator. You need to use atleast two players starting hands. Which means you will need to re-formulate my formula above. Since there are two or more SEEN cards.

Friday, July 14, 2006

CDPoker : Don't Try It.

Hey Guys,

Today I was browsing through the Internet. I seen a discussion about CDPoker, and how awful they are. I am wanting to say I AGREE. I deposited some money into an account there. I didn't get my bonus put into my account, as I should have. So I decided to call customer service.

It took me ten or so, times until I got someone on the line. Once I did get someone to say hello cdpoker. They muttered in a foreign voice "h#ll no!" and HUNG UP. Before I even could say hello myself. I was a little furious, of course.

My advice, do not deposit your own money at CDPoker. Not even for rake back as I have seen everywhere. IT'S NOT WORTH IT.

Thursday, July 13, 2006

Combinations Part II: Starting Hands

Hey

Last posts I posted was about the basics of combinations. This post is going to be about how combinations are used when trying to figure out texas holdem starting hands.

People keep saying there are 1326 possible starting hands. How do they get this number?

There is 52 cards in a deck of cards. When I am dealt my first card for my starting hand there is 52 possibilities. Then I am dealt my second card for 51 possibilites. (X) Objects Taken From.

Now that we were dealt 2 cards for our starting hand. This is our (Y) At a Time part of the formula.

The formula looks like this:
(52)
(2)

52 x 51-------2652
_______ = ________ = 1326 number of possible starting hands
2 x 1------------2



Have you ever wondered? Why people say being dealt any pocket pair in texas holdem is 220 to 1?

There is 52 cards in the deck, I am dealt a pocket pair. When I was dealt my first card, There were 4 possibilities of getting this card. Then my second card dealt to me was the same rank. There were 3 possibilites of me getting another card of the same rank. These two possibilies is what we call our (X) Objects Taken From.

Since we are choosing 2 cards at a time. This would be our (Y) At a Time - part of the formula. Remember were dealt our 1st card. Then dealt our 2nd card. Which would represent 1 x 2 = 2.

Our formula for being dealt a pocket pair is below.
(4)
(2)

4 x 3-----------12
______ = __________ = 6
2 x 1------------2

Now, that we figured out the combination for pocket pairs. We need to divide this 6 by the total number of starting hands.

6 / 1326 = 221; or 220 to 1 that we will be dealt a pocket pair in holdem.


Now. What is the possibility I am dealt two suited cards? If we are looking for two hearts out of a 52 card deck we then set up our formula as:

(13) We have 13 hearts to Take From
(2) We are only choosing 2 cards At A Time.

13 x 12-------156
_______ = _______ = 78
2 x 1----------2

Now we divide 78 by 1326 the total possible starting hands.

78 / 1326 = 17; or 16 to 1 - that you will be dealt two suited cards that are hearts.


The starting hands fomula's here can be used on further but I will be writing forever. Play with these numbers and see what you come up with. I don't know what my next post will be about.

Basic Part of Math Poker - Combinations

Hey Guys,

Last week one night I was playing a 1-2 NL holdem cash game at the bar. I heard someone blurt out "330!" Then another man said "250". I look up at the T.V. to see what they were yelling about. I seen a trivia question from the Full Tilt Poker show. The question was, "What are the odds that you are dealt pocket aces?" I laughed and then blurted out 220 to 1. Of course I was right, but I was amazed that these guys didn't know the answer. These guys are fairly good players too. They asked, "how did I know that"? I explained it to them in a formula sense. Then it dawned on me that how many people don't understand their Combinations for poker math.


Example.

The other day I played 5 card draw. Each player is dealt a 5 card hand from a 52 card deck. I wanted to figure out how many possible 5 card hands there are.

No problem. There are 52 possibilities for the first card, then 51 possibilities left for the second card. 50 possibilities for the third card, then 49 possibilites, then 48 possiblilities. So the total number of hands is

52 x 51 x 50 x 49 x 48 = 311,875,200

There is something wrong. What we have here is a permutation. We will have some hands that have the same exact cards.

Example of a permutation --- See below we have the exact same cards just in a different order.
7 of hearts, king of hearts, 10 of spades, 3 of diamonds, ace of clubs
king of hearts, 7 of hearts, 10 of spades, 3 of diamonds, ace of clubs

We are wanting different combinations of hands. Number of different ways of chosing the 5 cards in our hand.

We realize that there are 120 ways of putting 5 objects in order.
5 x 4 x 3 x 2 x 1 = 120 another permutation.

The number 311,875,200 is 120 times to big to be considered a combination. Therefore, the number of 5 card hands, when you don't want to count each different ordering seperately, must be:

52 x 51 x 50 x 49 x 48 -------311,875,200
__________________ = _______________ = 2,598,960
5 x 4 x 3 x 2 x 1-------- ----------120


The numbers of ways of selecting objects in this way is called the number of Combinations of X objects taken Y at a time. When you count the number combinations, the order of the objects what you select does not matter. Notice that the number of combinations is therefore less than the number of permutations.

Combinations are expressed as:
(X)
(Y)

(X)
(Y) : This expression is sometimes read as "X choose Y," because it tells you the number of different ways of choosing Y objects from a group of X objects.


One more small Example.

I am a coach of a baseball team. I only have 9 players on my team. Just enough to fill my batting order. I don't know which order I want my players to bat. I am going to figure out how many different ways I can order my roster.

9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 362,880 This is another permuatation, not combinations

Okay, Now I am going to figure out how many different combinations are there in my roster.

Our formula is expressed as :
(X) Objects Taken from
(Y) At a time

(9) Objects Taken from
(9) At a time

9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1----362,880
________________________ = ___________ = 1
9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1----362,880



Now, If I had 12 players to fill my 9 ordered roster it would look like this

(12) Objects Taken from
(9) At a time

12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4------79,833,600
___________________________ = ________________ = 220
9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1------------362,880


Do you see how these 3 different people on the same 9 order batting roster made a big difference?

Okay, I hope you learned something here. Next posts will be how to use these combinations into starting hand formulas. Feel free to ask questions - email me or post a comment.

Welcome, This is My Introduction.

Hey, Welcome to my blog

I call myself undream2. I have been playing poker for about 12 years now. I started out by playing 7 card stud mostly, Great Game. I have created this blog to help all levels of poker players. I am no poker pro, so this blog isn't going to be about how I took all of Doyle Brunson's money at a cash game. However, I am going to provide quality information about poker and odds.

If there is anything you would like to see discussed email me.

Also as my first post. Contact your state gov't about the banning of poker at http://www.pokerplayersalliance.org/